note that if you do float f = (float)rand(); it will convert the integer into a float (thus 10 will become 10.0). So now if you want to limit the maximum value you can do something like (not sure if this works) int tmp = rand(); float f = *((float*)&tmp); tmp = (unsigned int)f // note float to int conversion! tmp %= max_number; f -= tmp; WebJun 15, 2024 · 其中有两个位运算,一个是>>,一个是&。 0xff的作用一: 十六进制0xff的长度是一个字节,即八位,二进制为:1111 1111,那么一个 8bit 数与1111 1111与运算还是这个数本身, 但是一个16bit 数与 0xff就被截断了,比如 1100110011001100 & 0xff结果为 11001100 。 那如果想不被截断怎么办? 把0xff扩展为二个字节即:0xffff,那么以此类 …
int val=rand() & 0xFF 是什么意思? - CSDN博客
WebNov 16, 2012 · @GlennMaynard: If you were dividing by (RAND_MAX+1ULL) (presumably a power of 2), you'd just be scaling the FP exponent. Some rounding is actually necessary: if you want to generate uniform float value over [0..1], but still have a chance to generate every representable float, you need multiple integer values to round to the same final float for … WebDec 29, 2024 · 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 how can eagles clinch division
How to generate random float number in C - Stack Overflow
WebJun 8, 2015 · I'm learning c++ and I'm trying to generate a random float and seem to be having some difficulties. I start by making a random int(), newRandom, between -100 and 100, then I take that newRandom and turn it into a random float, rand_X, between -1.0 and 1.0. The only caveat is I don't want rand_X to be between -0.2 and 0.2, in other words, WebMar 10, 2016 · 1 ip [i] = (float) (rand & 0xFF) / 10.0f; 配列の各要素に乱数を与えて配列の初期値を設定する部分です。 "rand() & 0xFF" 全体に対して括弧でくくりfloatのキャスト変 … WebAug 26, 2024 · ip [i] = ( float ) ( rand () & 0xFF) / 10.0f; } } // modify sumArrayOnHost to sumArrayOnDevice. __global__ void sumArrayOnDevice(float * a, float * b, float * c) {. c … how can earn money from google